If brown hair is dominant over blonde hair, cross a heterozygous brown haired father with a homozygo

If brown hair is dominant over blonde hair, cross a heterozygous brown haired father with a homozygous blonde mother. Summarize the genotype and phenotype of their 4 children.

If brown hair is dominant over blonde hair, cross a heterozygous brown haired father with a homozygous blonde?

"If brown hair is dominant over blonde hair, cross a heterozygous brown haired father with a homozygous blonde mother."

Heterozygous brown father = Bb

Homozygous blonde mother = bb

Bb x bb

__B___b

b_Bb_bb

b_Bb_bb

"Summarize the genotype and phenotype of their 4 children."

2 heterozygous brown, 2 homozygous blonde

If brown hair is dominant over blonde hair, cross a heterozygous brown haired father with a homozygous blonde?

There are only 2 possible progeny. If W= brown and b= blonde, then you have Bb x bb. The child could be Bb or bb. Thus, there is a 50% chance of a brown haired child (Bb) and 50% chance of blonde haired child.

All this assumes that human haircolor follows mendelian genetics.

If brown hair is dominant over blonde hair, cross a heterozygous brown haired father with a homozygous blonde?

The genotype can mix as follows:

brown/blond, blond/blond.

brown/blond, blond/blond

The phenotype will be 50% chance of brown-haired children, 50% chance of blond-haired children.

If brown hair is dominant over blonde hair, cross a heterozygous brown haired father with a homozygous blonde?

B=brown, b=Blondie

Bbxbb= Bb, bb, bb, Bb

the genotypic ratio would be 1:1 (1 Bb to each bb)

the phenotypic ratio would also be 1:1 (1 brunette to each Blondie)

If brown hair is dominant over blonde hair, cross a heterozygous brown haired father with a homozygous blonde?

If the allele for brown hair is "B" and that of blonde is "b", then the ratios will be:

25% of their children will be heterozygous brown haired and 75% of their children will be homozygous blonde, hence the ratios are 3:1.